Join function is joining a number of sub strings contained in an array. This string joint by delimiter specified in our syntax. Therefore we must understand well what array is before used. The detail array is Here. There are rules to follow:
1) Only single dimension array are allow.
2) Only Sting or Variant data type otherwise error "Run-time error '5': Invalid procedure call or argument.
3) To joint with space then we use " ".
4) To joint with nothing then we use "".
5) Be careful with start point either 0 or1 (Option Base 1), if we use Option Base 1 then we must start with 1 otherwise start with 0. Joining result is not accurate when start point is not matched.
Syntax : Join(Array, [delimiter]), Return : Array(0) delimiter Array(1) delimiter Array(2) ....
Below example is to joint String data type with delimiter comma (,):
VBA Vode:
Option Base 1 ' Set default array subscripts to 1.
Sub Examples_JoinString()
Dim StrVar() As String
ReDim Preserve StrVar(1): StrVar(1) = "Tutorial VBA"
ReDim Preserve StrVar(2): StrVar(2) = "Excel VBA"
ReDim Preserve StrVar(3): StrVar(3) = "Programming"
ReDim Preserve StrVar(4): StrVar(4) = "Excel Formula"
ReDim Preserve StrVar(5): StrVar(5) = "Visual Basic"
Debug.Print Join(StrVar, ",")
End Sub
Note:
The answer for the above is:
Tutorial VBA,Excel VBA,Programming,Excel Formula,Visual Basic
If we never put Option Base 1 at module level the result will different and not accurate because we never assigned StrVar(0) value. The result as below:
,Tutorial VBA,Excel VBA,Programming,Excel Formula,Visual Basic
Other Reference-Join-function
Practice makes perfect. Thank You.
macro enabled excel
excel macro
vba coding
vba code
No comments:
Post a Comment